Question 1

Below is a function machine.

1(a):

What is the output if the input is 5?

ANSWER: Simple Text Answer

Answer: 12

Workings:

29+8=37

37-15=22

Marks = 2

 

1(b):

What is the input if the output is 29?

ANSWER: Simple Text Answer

Answer: 22

Workings:

29+15=44

44-8=36

Marks =  2


Question 2

Considering the new function machine below.

2(a):

What is the output if the input is 9?

ANSWER: Simple Text Answer

Answer: 18

Workings:

9\times 8 = 72

72\div 4 = 18

Marks = 2

 

2(b):

What is the input if the output is 14?

ANSWER: Simple Text Answer

Answer: 7

Workings:

14\times 4 = 56

56\div 8 = 7

Marks = 2


Question 3

Below is a function machine.

3(a):

What is the output if the input is 56?

ANSWER: Simple Text Answer

Answer: 17

Workings:

56\div 7 =8

8+9=17

Marks = 2

 

3(b):

What is the input if the output is 10?

ANSWER: Simple Text Answer

Answer: 7

Workings:

14\times 4 = 56

56\div 8 = 7

Marks = 2


Question 4

Below are some empty function machines.

4(a):

The number 48 is input into the machine.

The output is 18.

Fill in the missing operation.

ANSWER: Multiple Choice (Type 1)

A: +5

B: +6

C: +7

D: +8

Answer: B

Workings:

48\div 4 = 12

We need to get from 12 to 18.

The simplest way of doing this is just to add 6.

12+6=18

Marks = 2

 

4(b):

The number 18 is input into the machine.

The output is 26.

Fill in the missing operation.

ANSWER: Multiple Choice (Type 1)

A: +5

B:-7

C:\times 6

D: \div 9

Answer: D

Workings:

26 \div 13 = 2

We need to get back from 2 to 18.

The easiest way to do this is to multiply by 9.

Because we are working backwards the operator will be \div 9.

18\div 9 =2

2\times 13 = 26

Marks = 2

 

4(c):

The number 3 is input into the machine.

The output is 80.

Fill in the missing operation.

ANSWER: Multiple Choice (Type 1)

A: \times 30

B: - 20

C: + 10

D: \div 40

Answer: A

Workings:

Working backwards

80+10=90

We need to get from 90 to 3.

The easiest way to do this is divide by 30, but because we’re working backwards the operator will be \times 30.

3\times 30 = 90

90-10=80

Marks = 2


Question 5

5(a):

Complete the number machine so that a=2b-6.

 

ANSWER: Multiple Choice (Type 1)

A: Box 1: \times 2   Box 2: +3

B: Box 1: \times 2   Box 2: -6

C: Box 1: \div 2   Box 2: +2

D: Box 1: \times 3   Box 2: -1

Answer: B

Workings:

To get to 2b we need to multiply by 2 so the Box 1 operator will be \times 2.

We then need to subtract 6, so the Box 2 operator will be -6.

This gives us a=2b-6

Marks = 2

 

5(b):

Complete the number machine so that a=\dfrac{2+b}{3}

ANSWER: Multiple Choice (Type 1)

A: Box 1: +3   Box 2: \div 5

B: Box 1: -1   Box 2: \times 4

C: Box 1: +2   Box 2: \div 3

D: Box 1: +1   Box 2: \times 2

Answer: C

Workings:

To get b+2 we need to add 2, so the Box 1 operator will be +2.

We then need to divide by 3, so the Box 2 operator will be \div 3.

This gives us a=\dfrac{b+2}{3}.

Marks = 2

 

5(c):

Look at the function machine shown below.

Write down the output a, in terms of b.

ANSWER: Multiple Choice (Type 1)

A: 7b-14

B: 4b+7

C: -2b+7

D: -7b+2

Answer: A

Workings:

We first subtract 2 to get b-2.

Multiplying this by 7 gives 7(b-2).

Expanding this gives 7b-14.

Marks = 2


6(a):

Below are some empty function machines.

Which of the four options would take an input of 5 and give an output of 12.

ANSWER: Multiple Choice (Type 1)

A: Box 1: \div 4   Box 2: +7

B: Box 1: +3   Box 2: \times 4

C: Box 1: \times 2   Box 2: +2

D: Box 1: -1   Box 2: \div 2

Answer: C

Workings:

Multiplying by 2 will give us 10.

We can then add 2 to get 12.

So Box 1 = \times 2 and Box 2 = +2.

Marks = 2

 

6(b):

Which of the four options would take an input of 27 and give an output of 13?

ANSWER: Multiple Choice (Type 1)

A: Box 1: \div 3   Box 2: +4

B: Box 1: +4   Box 2: \div 3

C: Box 1: -5   Box 2: \div 2

D: Box 1: \div 2   Box 2: +1

Answer: A

Workings:

Dividing 27 by 3 gives 9.

Adding 4 to this then gives us 13.

So Box 1 = \div 3 and Box 2 = +4.

Marks = 2


Question 7

Below is a function machine.

7(a):

The number x is put through the machine.

The result is 3x.

What is x?

ANSWER: Simple Text Answer

Answer: 5

Workings:

We can write this as an equation: 6x-15=3x.

Rearranging gives 3x=15.

x=5

Marks = 3

 

7(b):

The number x is put through the same machine.

The result is 5x.

What is x?

ANSWER: Simple Text Answer

Answer: 15

Workings:

We can write this as an equation: 6x-15=5x.

Rearranging gives us x=15.

Marks = 3