Question 1

Work out the value of each function.

1(a):

If f(x) = x -10, find f(20)

ANSWER: Simple Text Answer

Answer: 10

Workings:

Substitute x=20 into the equation

f(20)=20-10=10

Marks = 1

 

1(b):

If g(x)= \dfrac{-x}{4}, find g(-40)

ANSWER: Simple Text Answer

Answer: 10

Workings:

Substitute x=-40 into the equation

g(-40)=\dfrac{40}{4}=10

Marks = 1

 

1(c):

If f(x)=\dfrac{-x^2+10}{5}, find f(5)

ANSWER: Simple Text Answer

Answer: -3

Workings:

Substituting x=5 into the equation gives

f(5)=\dfrac{-5^2+10}{5}=\dfrac{-15}{5}=-3

Marks = 1

 

1(d):

If h(x)= -5(x -2)^2, find h(12)

ANSWER: Simple Text Answer

Answer: -500

Workings:

Substituting x=12 into the equation gives

h(12)=-5(12-2)^2 = -5\times 10^2=-5\times 100=-500

Marks = 1

 

1(e):

If g(x)=\dfrac{x-3}{4}, find g(83)

ANSWER: Simple Text Answer

Answer: 20

Workings:

Substituting x=83 into the equation gives

g(83)=\dfrac{83-3}{4}=\dfrac{80}{4}=20

Marks = 1


Question 2

A function is given by f(x) = 3x+3

What are the values of boxes 1-4?

ANSWER: Multiple Choice (Type 1)

A: Box 1 = 12,   Box 2 = -6,   Box 3 = f(0),   Box 4 = 3a+3

B: Box 1 = 15,   Box 2 = -2,   Box 3 = f(-1),   Box 4 = a+3

C: Box 1 = 10,   Box 2 = 1,   Box 3 = f(3),   Box 4 = a

D: Box 1 = 7,   Box 2 = 0,   Box 3 = f(1),   Box 4 = a+1

Answer: A

Workings:

Box 1 = f(3)=3\times 3+3= 12

Box 2 = f(-3)=3\times-3 + 3=-6

Box 3 = 3x+3=3 so rearranging gives x=0

Box 4 = f(a)=3a+3

Marks = 2


Question 3

Considering the function f(x)=2x^2-1

3(a):

Using the table, what are the values for boxes 1 – 4?

ANSWER: Multiple Answers (Type 1)

Answer: Box 1 = 1,   Box 2 = 21,   Box 3 = 7,   Box 4 = 1

Workings:

Box 1 = f(-1)=2\times (-1)^2-1=2\times 1-1=2-1 =1

Box 2 = f(4)=2\times 4^2-1=2\times 16-1=32-1=31

Box 3 = f(2) =2\times 2^2-1=2\times 4-1=2\times 4-1=8-1=7

Box 4 = f(1)=2\times 1^2-1=2\times 1-1=2-1=1

Marks = 1

 

3(b):

Using the table, what is the value of Box 5?

ANSWER: Multiple Choice (Type 1)

A: b^2-2

B: 3b^2+1

C: 2b^2-1

D: -b^2+2

Answer: C

Workings:

Box 5 = f(-b)=2\times (-b)^2-1=2\times b^2-1=2b^2-1

Marks = 1


Question 4

Given that f(x) = (x-5)^2, find:

4(a):

f(3)

ANSWER: Simple Text Answer

Answer: 4

Workings:

f(3)=(3-5)^2=(-2)^2=4

Marks = 1

 

4(b):

f(0)

ANSWER: Simple Text Answer

Answer: 25

Workings:

f(0)=(0-5)^2=(-5)^2=25

Marks = 1

 

4(c):

If f(x) = 0find the value of x

ANSWER: Simple Text Answer

Answer: x=5

Workings:

(x-5)^2=0

x-5=0

x=5

Marks = 2


Question 5

Solve the following functions.

5(a):

f(x) = x -10

Solve f(x) = 0

ANSWER: Simple Text Answer

Answer: x=10

Workings:

f(x)=x-10=0

x=10

Marks = 1

 

5(b):

g(x)= \dfrac{-x}{4}

Solve g(x) = 0.25

ANSWER: Simple Text Answer

Answer: x=-1

Workings:

g(x)=\dfrac{-x}{4}=0.25

-x=1

x=-1

Marks = 1

 

5(c):

f(x)=\dfrac{x^2+11}{5}

Solve f(x)=12

ANSWER: Multiple Choice (Type 1)

A: \pm 4

B: \pm 5

C: \pm 6

D: \pm 7

Answer: D

Workings:

f(x) = \dfrac{x^2+11}{5}=12

x^2+11=60

x^2=49

x=\pm 7

Marks = 2

 

5(d):

h(x)=-5(x-2)^2

For which values of x does h(x) = -5?

ANSWER: Multiple Answers (Type 2)

Answer: x=1 & x=3

Workings:

h(x)=-5(x-2)^2=-5

(x-2)^2=1

x-2=\pm 1

[latex]x=1 OR x=3

Marks = 2