Question 1:
The cost-per-minute of call time used on a monthly phone contract for RiffRaff is displayed in the graph below.
Question 1(a): [2 marks]
A customer uses 150, 300, and 50 minutes in three consecutive months.
What is the total cost of the contract over the three months?
Answer type: Simple text answer
ANSWER: £44
WORKING:
Read the data of the graph, as seen by the lines below.
10 + 14 + 20 = £44.
Question 1(b): [2 marks]
Using the graph, find an equation for the total cost per month, C, in terms of minutes used, M.
Choose the correct equation.
Answer type: Multiple choice type 1
A: C = \dfrac{1}{25}M + 8
B: C = 25M + 8
C: C = \dfrac{1}{25}M - 8
D: C = 25M - 8
ANSWER: A: C = \dfrac{1}{25}M + 8
WORKING:
\text{Gradient } = \dfrac{1}{25}
y-\text{intercept } = 8
Question 1(c): [2 marks]
A rival company Purple, has the a monthly contract that follows the grey line seen on the graph.
Determine the price and number of minutes where both contracts have the same value.
Answer type: Multiple answers type 1
ANSWER:
Cost = £16
Minutes = 200
WORKING:
Find the values where the two graphs cross.
Question 2:
The conversion graphs below show the relationship between the value of the pound and dollar, and the value of the pound and euro.
Question 2(a): [2 marks]
After a holiday Ben has \$ 441 and € 318 remaining.
What is the total value of Ben’s remaining money in pounds?
Answer type: Simple text answer
ANSWER: £580
WORKING:
\$ 7 = £5, so \$ 441 = \dfrac{441}{7} \times 5 = 63 \times 5 = £315.
€ 6 = £5, so € 318 = \dfrac{318}{6} \times 5 = 53 \times 5 = £265.
Total: £315 + £265 = £580.
Question 2(b): [2 marks]
Convert \$ 252 into euros.
Answer type: Simple text answer
ANSWER: 216 euros
WORKING:
\dfrac{252}{7} \times 5 = 36 \times 5 = £180
\dfrac{180}{5} \times 6 = 36 \times 6 = €216
Question 3:
The table shows the costs of bicycle hire from two companies, WeBike and Wheely Good.
The total cost of the bicycle from Wheely Good has been plotted on the graph below.
Question 3(a): [2 marks]
Choose the correct plot from below, for the cost of WeBike over a week.
Answer type: Multiple choice type 1
A: A
B: B
C: C
D: D
ANSWER: D: D
Question 3(b): [1 mark]
Which company is better value for a week-long bicycle hire?
Answer type: Multiple choice type 1
A: WeBike
B: Wheely Good
C: Both the same
ANSWER: C: Both the same
Question 4:
For each of the following graphs, choose the best real life description of what it could represent.
Question 4(a): [1 mark]
Graph A.
Answer type: Multiple choice type 2
A: Throwing a ball
B: Not moving
C: Accelerating at a constant rate
ANSWER: A: Throwing a ball
Question 4(b): [1 mark]
Graph B.
Answer type: Multiple choice type 2
A: Throwing a ball
B: Accelerating at a constant rate
C: A buoy in the sea bobbing up and down
ANSWER: C: A buoy in the sea bobbing up and down
Question 5:
The diagram shows a container that is filled with water at a constant rate.
The graph shows the height of the water increasing until the container is full.
For each container, choose the matching graph below, for the height of water increasing until the container is full.
In each case the rate at which water flows into the container is constant.
Question 5(a): [1 mark]
Container A:
Answer type: Multiple choice type 1
A: Graph 1
B: Graph 2
C: Graph 3
D: Graph 4
ANSWER: C: Graph 3
Question 5(b): [1 mark]
Container B:
Answer type: Multiple choice type 1
A: Graph 1
B: Graph 2
C: Graph 3
D: Graph 4
ANSWER: B: Graph 2
Question 5(c): [1 mark]
Container C:
Answer type: Multiple choice type 1
A: Graph 1
B: Graph 2
C: Graph 3
D: Graph 4
ANSWER: D: Graph 4
Question 6: [2 marks]
The distance time graph shows the path of an object.
Calculate the average speed of the object between 1.5 seconds and 3.5 seconds.
Give your answer to 1 decimal place, in metres per second (m/s)
Answer type: Simple text answer
ANSWER: 1.6 m/s
WORKING:
Imagine drawing a straight line between the two points on the graph at 1.5 seconds and 3.5 seconds.
We find the average speed by calculating the gradient of this line.
\text{Gradient} = \dfrac{\text{Change in } y}{\text{Change in } x} = \dfrac{9.2-6}{3.5-1.5} = \dfrac{3.2}{2} = 1.6 m/s