Question 1(a): [1 mark]

For y = x^2, find the values of a, b, c, d, e from the table.

 

 

Answer type: Multiple answers type 1

ANSWER: a = 9 ; b = 4 ; c = 1 ; d = 0 ; e = 1

WORKING:

(-3)^2 = 9

(-2)^2 = 4

(-1)^2 = 1

(0)^2 = 0

(1)^2 = 1

 

 

 

Question 1(b): [1 mark]

What is the correct graph for y = x^2?

 

Answer type: Multiple choice type 1

A: A

B: B

C: C

D: D

ANSWER: A: A

 


 

Question 2(a): [1 mark]

For y = x^3 - 2x, find the values of a, b, c, d, e from the table.

 

 

Answer type: Multiple answer type 1

ANSWER: a = -4 ; b = 1 ; c = 0 ; d = -1 ; e = 4

WORKING:

(-2)^3 - 2(-2) = -4

(-1)^3 - 2(-1) = 1

(0)^3 - 2(0) = 0

(1)^3 - 2(1) = -1

(2)^3 - 2(2) = 4

 

 

 

Question 2(b): [1 mark]

What is the correct graph for y = x^3 - 2x?

 

Answer type: Multiple choice type 1

A: A

B: B

C: C

D: D

ANSWER: C: C

 


 

Question 3(a): [1 mark]

For A: y = x^2 - 1, -2 \leq x \leq 3, find the values of a, b, c, d, e, f from the table.

 

 

Answer type: Multiple answers type 1

ANSWER: a = 3 ; b = 0 ; c = -1 ; d = 0 ; e = 3 ; f = 8

WORKING:

(-2)^2 - 1 = 3

(-1)^2 - 1 = 0

(0)^2 - 1 = -1

(1)^2 - 1 = 0

(2)^2 - 1 = 3

(3)^2 - 1 = 8

 

 

Question 3(b): [1 mark]

For B: y = x^2 - x, -2 \leq x \leq 3, find the values of g, h, i, j, k, l from the table.

 

 

Answer type: Multiple answers type 1

ANSWER: g = 6 ; h = 2 ; i = 0 ; j = 0 ; k = 2 ; l = 6

WORKING: 

(-2)^2 -(-2) = 6

(-1)^2 -(-1) = 2

(0)^2 -(0) = 0

(1)^2 -(1) = 0

(2)^2 -(2) = 2

(3)^2 -(3) = 6

 

 

Question 3(c): [1 mark]

Choose the correct statement below about the graph drawings.

 

Answer type: Multiple choice type 1

A: A is drawn correctly but B is drawn incorrectly.

B: B is drawn correctly but A is drawn incorrectly.

C: Both A and B are drawn correctly.

D: Both A and B are drawn incorrectly.

 

ANSWER:  B: B is drawn correctly but A is drawn incorrectly.

WORKING:  The graph drawn that is incorrect is y = x^2 + 1, but it should be y = x^2 - 1.

 


 

Question 4(a): [1 mark]

What is the difference between a sketch and a plot of a graph?

 

Answer type: Multiple choice type 1

A:  A plot of a graph is more precise, using all the exact points. A sketch may use some of the known points that are then connected.

B: A sketch of a graph is more precise, using all the exact points. A plot may use some of the known points that are then connected.

C: There is no difference.

 

ANSWER:  A plot of a graph is more precise, using all the exact points. A sketch may use some of the known points that are then connected.

 

 

Question 4(b): [6 marks]

There are 6 equations as follows:

A: y = x^3 + 2x^2

B: y = x^3

C: y = -x^3

D: y = x^2

E: y = x^2 + 2x

F: y = -x^2

 

and 6 graphs:

Match the graphs to the equations.

 

Answer type: Multiple answers type 1

ANSWER:

Graph 1 = D

Graph 2 = B

Graph 3 = A

Graph 4 = E

Graph 5 = F

Graph 6 = C

 


 

Question 5(a): [1 mark]

The values for y = -x^3 + 3x^2 for x from -1 to [/latex]3[/latex] can be seen in the table below. 

 

Find the values of a, b, c, d, e from the table.

 

Answer type: Multiple answers type 1

ANSWER:

a = 4

b = 0

c = 2

d = 4

e = 0

 

WORKING:

-(-1)^3 + 3(-1)^2 = 4

-(0)^3 + 3(0)^2 = 0

-(1)^3 + 3(1)^2 = 2

-(2)^3 + 3(2)^2 = 4

-(3)^3 + 3(3)^2 = 0

 

 

 

Question 5(b): [2 marks]

What is the correct graph for y = -x^3 + 3x^2?

 

Answer type: Multiple choice type 1

A:  B:  C:  D: 

 

ANSWER: A

 


 

Question 6(a): [1 mark]

The values for y = \dfrac{1}{2}(x^3 + x + 1), for x from -2 to [/latex]3[/latex] can be seen in the table below.

 

Find the values of a, b, c, d, e from the table.

 

Answer type: Multiple answers type 1

ANSWER:

a = -4.5

b = -0.5

c = 0.5

d = 1.5

e = 5.5

 

WORKING:

\dfrac{1}{2}( (-2)^3 + (-2) + 1) = -4.5

\dfrac{1}{2}( (-1)^3 + (-1) + 1) = -0.5

\dfrac{1}{2}( (0)^3 + (0) + 1) = 0.5

\dfrac{1}{2}( (1)^3 + (1) + 1) = 1.5

\dfrac{1}{2}( (2)^3 + (2) + 1) = 5.5

 

 

 

Question 6(b): [2 marks]

What is the correct graph for y = \dfrac{1}{2}(x^3 + x + 1)?

 

Answer type: Multiple choice type 1

A:  B:  C:  D: 

 

ANSWER: A