Question 1
The table below shows the density, mass and volume of different objects.
Calculate the density of object A in g/m^3.
Give your answer in g/m^3.
ANSWER: Simple text answer
Answer: 18000000 g/m^3
Workings:
27000 \div 0.0015 = 18000000 g/m^3
Use the formula \text{density} = \dfrac{\text{mass}}{\text{volume}}
Marks = 2
1(b) Complete the table by calculating values for X in kg/cm^3, Y in g and Z in cm^3.
ANSWER: Multiple answers (Type 1)
Answers:
X = 0.018 kg/cm^3
Y =24050 g
Z = 0.3 cm^3
Workings:
Use of density formula as in part(a).
Marks = 3
Question 2
The diagram shows a wooden block with density 0.57 g/cm^3
Calculate the mass of the cube.
Give your answer in grams.
ANSWER: Simple text answer
Answer: 34.2 g
Workings:
Volume = 3 cm \times 4 cm \times 5 cm = 60 cm^3
\text{Mass} = \text{Density} \times \text{Volume} = (0.57 g/cm^3) \times (60 cm^3) = 34.2 g
Marks = 3
Question 3
3(a) Iron has a density of 7.8 g/cm^3
Calculate the mass of a 3 cm^3 lump of iron.
ANSWER: Simple text answer
Answer: 23.4 g
Workings:
\text{Mass}=\text{Density} \times \text{Volume}= (7.8 g/cm^3) \times (3 cm^3) = 23.4g/latex] g</p> <p style="text-align: left;"><strong>Marks </strong>= 2</p> <p> </p> <p>3(b) Aluminium has a density of [latex]2.7 g/cm^3
Calculate the difference between the volume of a 5 g lump of iron and a
5 g lump of aluminium.
ANSWER: Simple text answer
Answer: 1.21 cm^3
Workings:
Iron: 5 \div 7.8 = 0.64 m^3
Aluminium: 5 \div 2.7g = 1.85 cm^3
Difference: (1.85 cm^3) - (0.64 cm^3) = 1.21 \space cm^3
Marks = 3
Question 4
A steel rod is in the shape of a cylinder, shown below.
The steel rod has a density of 9.8 \space g per cm^3.
The rod has a volume of 60 \space cm^3.
Calculate the mass of the rod in grams.
ANSWER: Simple text answer
Answer: 588 g
Workings:
\text{Mass} = \text{Density} \times \text{Volume} = (9.8 g/cm^3) \times (60 cm^3) = 588 g
Marks = 2
Question 5
The diagram below shows a cuboid.
Width is 6 \space cm
Height is 3 \space cm
Length is x \space cm
5(a) The cuboid is made from wood and has a mass of 233.1 \space g.
The density of wood is 1.85 \space g/cm^3.
Calculate the volume of the cuboid.
Give your answer in cm^3
ANSWER: Simple text answer
Answer: 126 cm^3
Workings:
233.1 \div 1.85 = 126 cm^3
Marks = 2
5(b) Hence, or otherwise, find the missing length x of the cuboid.
ANSWER: Simple text answer
Answer: 7 cm
Workings:
126\div (3 \times 6) = 7 cm
Marks = 1
Question 6
The diagram shows a spherical glass paperweight with a radius of 4 \space cm.
The density of glass is 8 g/cm^3.
Volume of a sphere = \dfrac{4}{3}\pi r^3
Calculate the mass of the paperweight.
Give your answer correct to 3 significant figures.
ANSWER: Simple text answer
Answer: 2140 g
Workings:
Volume = \dfrac{4}{3} \pi \times 4^3 = 268 cm^3
Mass = 8 \times 268 = 2140 g
Marks = 3