Question 1

y is directly proportional to x.

When y = 36, x = 4

1(a) Find a formula for y in terms of x

ANSWER: Simple text answer

Answer: y = 9x

Workings:

y = kx

36 = 4k so k = 9

y = 9x

Marks = 3

 

1(b) Find the value of y when x = 3.

ANSWER: Simple text answer

Answer: 27

Workings:

y = 9 × 3 = 27

Marks = 1


Question 2

y is directly proportional to x^2.

When x=2, y = 36.

2(a) Find a formula for y in terms of x.

ANSWER: Multiple choice (Type 1)

A: y = 3x^2

B: y = \dfrac{x}{4}x^2

C: y = 9x^2

D: y = 3x

Answer: C

Workings:

y = kx^2

36 = 4k, k = 9

y = 9x^2

Marks = 3

 

2(b) Find the value of x when y = 49

Give your answer as a fraction.

ANSWER: Fraction

Answer: x=\dfrac{7}{3}

Workings:

49 = 9x^2 so x^2 = \dfrac{49}{9}

x = \sqrt{\dfrac{49}{9}} = \dfrac{7}{3}

Marks = 1


Question 3

In the table below, d is directly proportional to c

3(a) Find a formula for d in terms of c

ANSWER: Simple text answer

Answer: d = 4c

Workings:

d= kc

12 = 3c so k = 4

d = 4c

Marks = 3

 

3(b) Hence, or otherwise, find the values of X. Y and Z to complete the table above.

ANSWER: Multiple answers (type 1)

Answer: X = 7, Y = 20, Z = 48

Workings:

Y = 4\times 5 = 20

X = \dfrac{28}{4} = 7

Z = 12\times 4 = 48

Marks = 3


Question 4

x is inversely proportional to y

when x = 7, y = 4.

4(a) Find a formula for y in terms of x

ANSWER: Multiple choice (Type 1)

A: y = \dfrac{28}{x}

B: y = \dfrac{x}{28}

C: y = \dfrac{4k}{7}

D: y = \dfrac{7k}{4}

Answer: A

Workings:

x = \dfrac{k}{y} so 7=\dfrac{k}{4}

So x = \dfrac{28}{y}  so  y = \dfrac{28}{x}

Marks = 3

 

4(b) Find the value of x when y =2

ANSWER: Simple text answer

Answer: 14

Workings:

x = \dfrac{28}{2} = 14

Marks = 1


Question 5

y is inversely proportional to the square of x.

y=3 when x = 4.

5(a) Find a formula for y in terms of x

ANSWER: multiple choice (Type 1)

A: y = \dfrac{12}{x^2}

B: y = \dfrac{48}{x}

C: y = \dfrac{48}{x^2}

D: y = \dfrac{3k}{16}

Answer: C

Workings:

y = \dfrac{k}{x^2}

3 = \dfrac{k}{4^2} so k = 48

y = \dfrac{48}{x^2}

Marks = 3

 

5(b) Find the value of y when x = 5

Give your answer as a fraction.

ANSWER: fraction

Answer: \dfrac{48}{25}

Workings:

y = \dfrac{48}{5^2} = \dfrac{48}{25}

Marks = 1


Question 6

If r is inversely proportional to b^2 and r = 4 when b = 4.

6(a) Find the formula for r in terms of b.

Give your answer as a fraction.

ANSWER: fraction

A: r = \dfrac{64}{b^2}

B: r = \dfrac{16}{b}

C: r = \dfrac{64}{b}

D: r = \dfrac{16}{b^2}

Answer: A

Workings:

r \alpha \dfrac{1}{b^2}

r = \dfrac{k}{b^2}

4 = \dfrac{k}{(4)^2} so k = 64

r = \dfrac{64}{b^2}

Marks = 3

 

6(b) Find the value of r when b = 2

ANSWER: Simple text answer

Answer: 16

Workings:

r = \dfrac{64}{(2)^2} = \dfrac{64}{4} = 16

Marks = 1

 

6(c) Find the value of b when r = 2.

Give your answer to 3 significant figures.

ANSWER: Simple text answer

Answer: 5.66

Workings:

b^2 = \dfrac{64}{r} = \dfrac{64}{2} = 32

b = \sqrt{32} = 4\sqrt{2} = 5.66 (3 s.f.)

Marks = 2


Question 7

a, b and c are three variables.

a is proportional to b^2

a is also proportional to \sqrt{c}

b = 4.5 when c = 2.25

Find b when c = 8

Give your answer correct to 3 significant figures.

ANSWER: Simple text answer

Answer: 6.18

Workings:

a = kb^2 and a = m\sqrt{c}

So kb^2  = m\sqrt{c}

So b^2  = \dfrac{m}{k}\sqrt{c}

So b^2  \alpha  \sqrt{c}, so b^2 = g\sqrt{c}

g=\dfrac{b^2}{\sqrt{c}}= \dfrac{4.5^2}{\sqrt{2.25}} = 13.5

b^2 = 13.5 \sqrt{8}; b = 6.18

Marks = 6