Question 1

A triangle ABC is shown below:

Find the value of x

Select the correct answer from the list below:

A:  2.04 cm

B:  1.95 cm

C:  1.84 cm

D: 1.78 cm

 

CORRECT ANSWER:  

 

WORKED SOLUTION:

To find x we can use the sine rule,

\dfrac{a}{sin(A)}=\dfrac{b}{sin(B)}

Where is this instance we have,

\dfrac{3}{sin(75)}=\dfrac{x}{sin(35)}

Hence by reargning to make x the subject,

x=\dfrac{3sin(35)}{sin(75)}=1.78cm

Question 2

A triangle ABC is shown below:

Find the value of x

 

Select the correct answer from the list below:

A: 11.67 cm

B: 12.73 cm

C: 10.88 cm

D: 13.10 cm

 

CORRECT ANSWER:  

 

WORKED SOLUTION:

To find x we can use the sine rule,

\dfrac{a}{sin(A)}=\dfrac{b}{sin(B)}

Where is this instance we have,

\dfrac{15}{sin(40)}=\dfrac{x}{sin(30)}

Hence by reargning to make x the subject,

x=\dfrac{15sin(30)}{sin(40)}=11.67cm

Question 3

A triangle ABC is shown below:

Find the value of x

Select the correct answer from the list below:

A: 92.02 \degree

B: 87.48 \degree

C: 104.33 \degree

D: 96.09 \degree

 

CORRECT ANSWER:  

 

WORKED SOLUTION:

To find x we can use the sine rule,

\dfrac{sin(A)}{a}=\dfrac{sin(B)}{b}

Where is this instance we have,

\dfrac{sin(x)}{20}=\dfrac{sin(60)}{12}

Hence by rearranging to make x the subject,

x = 92.02 \degree

Question 4

A triangle ABC is shown below:

Find the value of x

Select the correct answer from the list below:

A: 16.71cm

B: 15.38cm

C: 17.95cm

D: 18.47cm

 

CORRECT ANSWER:  C: 17.95cm

 

WORKED SOLUTION:

To find x we can use the sine rule,

\dfrac{a}{sin(A)}=\dfrac{b}{sin(B)}

Where is this instance we have,

\dfrac{x}{sin(79)}=\dfrac{12}{sin(41)}

Hence by reargning to make x the subject,

x=\dfrac{12sin(79)}{sin(41)}=17.95cm

Question 5

A triangle ABC is shown below:

Find the value of x

Select the correct answer from the list below:

A: x=15.45

B: x=13.85

C: x=14.25

D: x=13.15

 

CORRECT ANSWER:  B: x=13.85

 

WORKED SOLUTION:

To find x we can use the sine rule,

\dfrac{a}{sin(A)}=\dfrac{b}{sin(B)}

Where is this instance we have,

\dfrac{x}{sin(91)}=\dfrac{12}{sin(60)}

Hence by rearranging to make x the subject,

x=13.85